Can I link from a list to a new screen?
So that when you press one of the components in the list, it sends you to a new screen. Which is originally blank, but I will design it after my choice.
Yes you can @parksidecreator . Choose the list and set the click action to a link action.
If you are adding any other components to the list then add actions individually for that components.
Thank you !! 
Dilon
@dilon_perera The list has 7 components, I want each component to take you to a individually designed page. Is still âClick actionâ â âlinkâ â ânew screenâ the solution? This will make all the 7 pages look the same and it wont let me play around with layout as far as I understand.
Hmm. @parksidecreator click the component and set the action
Do this logic to every component
Creator wonât let me chose components individually.
What . 
@parksidecreator click the list and then click components and then add the components.
Can you send a screen recording what is happening @parksidecreator ?
So just to be clear, you want to link to 7 different designed screens yah?
If so you can set conditionals like this
You will need another property in your collection to verify. In my case I used True/False
Is that what you meant?
I need a minute to comprehend what you just posted but it looks like what Iâm after.
This is my menu in preview mode, each button should lead to a new page with a new list. But this new page should have itâs own layout. So the main menu does not lead to 6 different pages, with the same layout.
@parksidecreator are you saying that in this list when you click one item it should have to go to a new screen with a list?
Am I correct?
Indeed thatâs right. But there are more components than just a list, on some of the pages, therefore Iâd like to have it lead to its own âNew Screenâ perhaps so I can set up set screen myself, individually.
Oh some pages have different different components know?
So yes, if you link the normal way each menu item will lead to the same screen pushing the collection data to that screenâŚ
The way I shown allows you to link to separate screens each carrying whatever layout you chooseâŚ
Now the 3rd way I had initially set got way out of hand and was a bother to update which is why I changed it to what I posted above.
This 3rd way I found cumbersome, so basically you combine the 2 prior solutions.
- The menu items link to 1 screen that is shared
- In this screen you will still need a property True/False or other to check
- You will have to âstackâ each layout on top of each other and set the visibility on them to the conditional property you have setup. (This is more effectively done by grouping each of them and set the visibility to Sometimes and the Property)
- So when the menu item is clicked, the linked screen will display whichever layout matches the Conditional property.
Yeah itâs confusing and very cumbersome hahah 
I wonât recommend it for anything past 2 layouts.
So you want to link with the list to that different different screens
I mean itâs an design issue, I donât want each page after the main menu to look the same, so I will set up what comes next differently. If itâs too difficult/impossible I will just create my own main menu by individually creating a new button for each page.
No. no read above you donât have to. Itâs way better to use Lists. 
I can make a cloneable later today when I get back if youâre still stuck
@tbel Was hoping I could give each page its own layout, so maybe method 2? 
@dilon_perera thanks for your input so far 
Method 2 for sure! Recommended. More scalable that way.